The number of geometric isomers that can exist for square planar [P t (C l) (p y) (N H3) (N H2 O H)]+ is (py = pyridine):

Question

The number of geometric isomers that can exist for square planar [P t (C l) (p y) (N H3) (N H2 O H)]+ is (py = pyridine): (A) 6 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

Complex with general formula [Mabcd]+ square planar complex can have three isomers. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-wujzlocmn8yuwuqe.jpg" />

Q. The number of geometric isomers that can exist for square planar $[Pt (Cl) (p y) (N H_{3}) (N H_{2} O H)]^{+}$ is (py = pyridine):

6

2

3

4

Complex with general formula $[M ab c d]^{+}$ square planar complex can have three isomers.

Q. The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH3​)(NH2​OH)]+ is (py = pyridine):

6

2

3

4

Complex with general formula [Mabcd]+ square planar complex can have three isomers.

Q. The number of geometric isomers that can exist for square planar $[Pt (Cl) (p y) (N H_{3}) (N H_{2} O H)]^{+}$ is (py = pyridine):

Complex with general formula $[M ab c d]^{+}$ square planar complex can have three isomers.