If number is divisible by 6, then it should be an even number and divisible by 3 also, so sum of the digits should be divisible by 3.
Now last digit can be fill by 0 or 2 or 4 . First place can be filled by 5 choices (except 0 ) second and third can be filled by 6 choices.
Now fourth place is filled such that it must be of form 3k or 3k+1 or 3k+2. So it can be fill by 2 choices (0 or 3) as whole number must be divisible by 3 so, total numbers =5×6×6×2×3 =1080