Question

The number of electrons required to deposit $1g$ -atom of Al (atomic mass $=27$ ) from a solution of $AlC{l}_3$ are :

• A. $1N$
• B. $2N$
• C. $3N$
• D. $4N$

Answer 1

Answer: (C)

$1g$ -atom of $Al=3$ eq. of $Al=3$ faraday charge
$3$ mole electrons $=3N$ electron.