The number of electrons passing per second through a cross-section of copper wire carrying 10-6 amperes of current per second is found to be

Question

The number of electrons passing per second through a cross-section of copper wire carrying 10-6 amperes of current per second is found to be (A) 1.6 × 10-19 (B) 6 × 10-35 (C) 6 × 10-16 (D) 6.24 × 1012

Tardigrade Admin · Accepted Answer

Charge (Coulombs) passing per second =10-6 Number of electrons passed per second =(10-6/1.602 × 10-19)=6.24 × 1012

Q. The number of electrons passing per second through a cross-section of copper wire carrying $1 0^{- 6}$ amperes of current per second is found to be

$1.6 \times 1 0^{- 19}$

$6 \times 1 0^{- 35}$

$6 \times 1 0^{- 16}$

$6.24 \times 1 0^{12}$

Charge (Coulombs) passing per second $= 1 0^{- 6}$

Number of electrons passed per second

$= \frac{1 0 ^{- 6}}{1.602 \times 1 0 ^{- 19}} = 6.24 \times 1 0^{12}$

Q. The number of electrons passing per second through a cross-section of copper wire carrying 10−6 amperes of current per second is found to be

1.6×10−19

6×10−35

6×10−16

6.24×1012