Question

The number of electrons passing per second through a cross-section of copper wire carrying $10^{-6}$ amperes of current per second is found to be

• A. $1.6 \times 10^{-19}$
• B. $6 \times 10^{-35}$
• C. $6 \times 10^{-16}$
• D. $6.24 \times 10^{12}$

Answer 1

Answer: (D)

Charge (Coulombs) passing per second $=10^{-6}$

Number of electrons passed per second

$=\frac{10^{-6}}{1.602 \times 10^{-19}}=6.24 \times 10^{12}$