Question

The number of electrons in any particle whose caries a charge of $3.2044\times 10-16C$, is

• A. $0.02\times 10^4$
• B. $2\times 10^{-3}$
• C. $2\times 10^3$
• D. $200$

Answer 1

Answer: (B)

Charge carried by one electron $=1.6022\times 10^{-19}C$
Electrons present in $3.2044\times 10^{-16}C=3.2044\times 10^{-16}/1.6022\times 10^{-19}=2\times 10^3$