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  4. The number of electrons in any particle whose caries a charge of 3.2044 × 10-16 C, is

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Q. The number of electrons in any particle whose caries a charge of $3.2044 \times 10-16 C$, is

Structure of Atom

Solution:

Charge carried by one electron $=1.6022 \times 10^{-19} C$
Electrons present in $3.2044 \times 10^{-16} C =3.2044 \times 10^{-16} /1.6022 \times 10^{-19}=2 \times 10^3$