The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (change on electron = 1.60 × 10-19 C)

Question

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (change on electron = 1.60 × 10-19 C) (A) 6 × 1023 (B) 6 × 1020 (C) 3.75 × 1020 (D) 7.48 × 1023

Tardigrade Admin · Accepted Answer

Q = ne I × t = ne n =(1 × 60/1.6 × 10-19) n =3.75 × 1020

Q. The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (change on electron = $1.60 \times 1 0^{- 19} C)$

$6 \times 1 0^{23}$

$6 \times 1 0^{20}$

$3.75 \times 1 0^{20}$

$7.48 \times 1 0^{23}$

$Q = n e$

$I \times t = n e$

$n = \frac{1 \times 60}{1.6 \times 1 0 ^{- 19}}$

$n = 3.75 \times 1 0^{20}$

Q. The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (change on electron = 1.60×10−19C)

6×1023

6×1020

3.75×1020

7.48×1023