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Q. The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (change on electron = $1.60 \times 10^{-19} C)$

NEETNEET 2016Electrochemistry

Solution:

$Q = ne$

$I \times t = ne$

$n =\frac{1 \times 60}{1.6 \times 10^{-19}}$

$n =3.75 \times 10^{20}$