Question

The number of electron in $2$ coulomb of charge is

• A. $5\times 10^{29}$
• B. $12.5\times 10^{18}$
• C. $6\times 10^{19}$
• D. $9\times 10^{11}$

Answer 1

Answer: (B)

Charge $q=ne$
$\therefore n=\frac{q}{e}=\frac{2}{1.6\times 10^{-19}}$
$=12.5\times 10^{18}$