Question

The number of divisors of $72,2025$ and $1568$ are in

• A. $A.P.$
• B. $G.P.$
• C. $A.G.P.$
• D. None of these

Answer 1

Answer: (A)

$72=2^3\times 3^2$; number of divisors of $72$ are $12$.
$2025=3^4\times 5^2$; number of divisors of $2025$ are $15$.
$1568=2^5\times 7^2$ ; number of divisors of $1568$ are $18$.
Now $12,15,18$ are in $A.P$.