Question

The number of de Broglie wavelengths contained in the second Bohr orbit of Hydrogen atom is

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$\because 2\pi r_n=n\lambda$
$\therefore n=2,2\pi r_2$
$=2\lambda =2\times$ de Broglie wavelength.