Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The number of bond pairs is X and lone pairs is Y on Xe (central atom) in XeO3F2 . What is the sum of X+Y ?
Q. The number of bond pairs is X and lone pairs is Y on Xe (central atom) in
X
e
O
3
F
2
. What is the sum of
X
+
Y
?
1682
247
NTA Abhyas
NTA Abhyas 2020
Chemical Bonding and Molecular Structure
Report Error
Answer:
5
Solution:
X
+
Y
=
8
+
0
=
8