The number of atoms in 0.1 mole of a triatomic gas is (NA = 6.023 × 1023 mol -1)

Question

The number of atoms in 0.1 mole of a triatomic gas is (NA = 6.023 × 1023 mol -1) (A)  6.026 × 1022 (B)  1.806 × 1023 (C)  3.600 × 1023 (D)  1.800 × 1022

Tardigrade Admin · Accepted Answer

Number of atoms = number of moles × NA × atomicity = 0.1 × 6.023 × 1023 × 3 = 1.806 × 1023 natoms

Q. The number of atoms in $0.1$ mole of a triatomic gas is $(N_{A} = 6.023 \times 1 0^{23} m o l^{- 1})$

$6.026 \times 1 0^{22}$

$1.806 \times 1 0^{23}$

$3.600 \times 1 0^{23}$

$1.800 \times 1 0^{22}$

Number of atoms $=$ number of moles $\times N_{A} \times$ atomicity
$= 0.1 \times 6.023 \times 1 0^{23} \times 3$
$= 1.806 \times 1 0^{23}$ natoms

Q. The number of atoms in 0.1 mole of a triatomic gas is (NA​=6.023×1023mol−1)

6.026×1022

1.806×1023

3.600×1023

1.800×1022