Question

The number of atoms in 0.1 mol of a tri atomic gas is $(N_A=6.02\times 10^{23}mo{l}^{-1})$

• A. $1.800\times 10^{22}$
• B. $6.023\times 10^{22}$
• C. $1.806\times 10^{23}$
• D. $3.600\times 10^{23}$

Answer 1

Answer: (C)

As for a tri atomic gas
Total no. of atoms $=n\times 3N_A=0.1\times 3\times 6.02\times 10^{23}=1.806\times 10^{23}atoms$