The nucleus of helium atom contains two protons that are separated by distance 3.0 × 10-15 m. The magnitude of the electrostatic force that each proton exerts on the other is

Question

The nucleus of helium atom contains two protons that are separated by distance 3.0 × 10-15 m. The magnitude of the electrostatic force that each proton exerts on the other is (A) 20.6 N (B) 25.6 N (C) 15.6 N (D) 12.6 N

Tardigrade Admin · Accepted Answer

Charge of proton is qp = 1.6 × 10-19 C Distance between the protons is, r = 3 × 10-15 m The magnitude of electrostatic force between protons is Fe=(qp qp/4πε0r2) =(9×109×1.6×10-19×1.6×10-19/(3×10-15)2) =25.6 N

Q. The nucleus of helium atom contains two protons that are separated by distance $3.0 \times 1 0^{- 15} m$ . The magnitude of the electrostatic force that each proton exerts on the other is

$20.6 N$

$25.6 N$

$15.6 N$

$12.6 N$

Q. The nucleus of helium atom contains two protons that are separated by distance 3.0×10−15m. The magnitude of the electrostatic force that each proton exerts on the other is

20.6N

25.6N

15.6N

12.6N

Charge of proton is qp​=1.6×10−19C Distance between the protons is, r=3×10−15m The magnitude of electrostatic force between protons is Fe​=4πε0​r2qp​qp​​ =(3×10−15)29×109×1.6×10−19×1.6×10−19​ =25.6N

Q. The nucleus of helium atom contains two protons that are separated by distance $3.0 \times 1 0^{- 15} m$ . The magnitude of the electrostatic force that each proton exerts on the other is

$20.6 N$

$25.6 N$

$15.6 N$

$12.6 N$