The nucleophillic additions of alkynes can be explained on the basis that alkynes form vinylic. carbanion, while alkenes form alkyl carbanion when attacked by nucleophile ( ddotN u) Thus vinylic carbanion (due to more a character) will be more stable than the alkyl carbanion (due to less a character). Hence alkynes are more liable to be attacked by a nucleophile than alkenes. CH ≡ CH + C2H5OH xrightarrowHgSO4 Y xrightarrowH2O X X is

Question

The nucleophillic additions of alkynes can be explained on the basis that alkynes form vinylic. carbanion, while alkenes form alkyl carbanion when attacked by nucleophile ( ddotN u) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/0a089556f46fdf2e4e0f4eafdd8fcb7d-.png" /> Thus vinylic carbanion (due to more a character) will be more stable than the alkyl carbanion (due to less a character). Hence alkynes are more liable to be attacked by a nucleophile than alkenes. CH ≡ CH + C2H5OH xrightarrowHgSO4 Y xrightarrowH2O X X is (A) CH 3 OH (B) C 2 H 5 OH (C) CH 3 CHO + C 2 H 5 OH (D) CH 2= CHOH

Tardigrade Admin · Accepted Answer

CH ≡ CH + C2H5OH arrow CH2 = CH . OC2H5 xrightarrowH2O CH3CHO + C2H5OH

$C H_{3} O H$

$C_{2} H_{5} O H$

$C H_{3} C H O + C_{2} H_{5} O H$

$C H_{2} = C H O H$

$C H \equiv C H + C_{2} H_{5} O H \to C H_{2} = C H . O C_{2} H_{5} H X_{2} O C H_{3} C H O + C_{2} H_{5} O H$

CH3​OH

C2​H5​OH

CH3​CHO+C2​H5​OH

CH2​=CHOH

CH≡CH+C2​H5​OH→CH2​=CH.OC2​H5​HX2​O​CH3​CHO+C2​H5​OH

$C H_{3} O H$

$C_{2} H_{5} O H$

$C H_{3} C H O + C_{2} H_{5} O H$

$C H_{2} = C H O H$

$C H \equiv C H + C_{2} H_{5} O H \to C H_{2} = C H . O C_{2} H_{5} H X_{2} O C H_{3} C H O + C_{2} H_{5} O H$