The net magnetic moment of two identical magnets each of magnetic moment M0 , inclined at 60° with each other is

Question

The net magnetic moment of two identical magnets each of magnetic moment M0 , inclined at 60° with each other is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-67dajnad1k81.png" /> (A) M0 (B) √2 M0 (C) √3 M0 (D) 2M0

Tardigrade Admin · Accepted Answer

Magnetic dipole moment is a vector quantity. Mn e t= √M02 + M02 + 2 M02 cos 60o = √3 M02= √3 M0

Q. The net magnetic moment of two identical magnets each of magnetic moment $M_{0}$ , inclined at $6 0^{\circ}$ with each other is

$M_{0}$

$2 M_{0}$

$3 M_{0}$

$2 M_{0}$

Magnetic dipole moment is a vector quantity.
$M_{n e t} = M_{0}^{2} + M_{0}^{2} + 2 M_{0}^{2} cos 6 0^{o}$
$= 3 M_{0}^{2} = 3 M_{0}$

Q. The net magnetic moment of two identical magnets each of magnetic moment M0​ , inclined at 60∘ with each other is

M0​

2​M0​

3​M0​

2M0​

Magnetic dipole moment is a vector quantity. Mnet​=M02​+M02​+2M02​cos60o​ =3M02​​=3​M0​

Q. The net magnetic moment of two identical magnets each of magnetic moment $M_{0}$ , inclined at $6 0^{\circ}$ with each other is

$M_{0}$

$2 M_{0}$

$3 M_{0}$

$2 M_{0}$

Magnetic dipole moment is a vector quantity.
$M_{n e t} = M_{0}^{2} + M_{0}^{2} + 2 M_{0}^{2} cos 6 0^{o}$
$= 3 M_{0}^{2} = 3 M_{0}$