The Nemst equation giving dependence of electrode potential on concentration is

Question

The Nemst equation giving dependence of electrode potential on concentration is (A) E=E°+(2.303 R T/n F) log ([M]/[Mn+]) (B) E=E°+(2.303 R T/n F) log ([Mn+]/[M]) (C) E=E°-(2.303 F/n R T) log ([Mn+]/[M]) (D) E=E°-(2.303 R T/n F) log [Mn+]

Tardigrade Admin · Accepted Answer

For Mn++n e- arrow M, E=E°-(2.303 R T/n F) log (M/[Mn+]) =E°+(2.303 R T/n F) log ([Mn+]/[M])

Q. The Nemst equation giving dependence of electrode potential on concentration is

$E = E^{\circ} + \frac{2.303 RT}{n F} lo g \frac{[ M ]}{[ M ^{n +} ]}$

$E = E^{\circ} + \frac{2.303 RT}{n F} lo g \frac{[ M ^{n +} ]}{[ M ]}$

$E = E^{\circ} - \frac{2.303 F}{n RT} lo g \frac{[ M ^{n +} ]}{[ M ]}$

$E = E^{\circ} - \frac{2.303 RT}{n F} lo g [M^{n +}]$

For $M n^{+} + n e^{-} \to M$ ,
$E = E^{\circ} - \frac{2.303 RT}{n F} lo g \frac{M}{[ M ^{n +} ]}$
$= E^{\circ} + \frac{2.303 RT}{n F} lo g \frac{[ M ^{n +} ]}{[ M ]}$

Q. The Nemst equation giving dependence of electrode potential on concentration is

E=E∘+nF2.303RT​log[Mn+][M]​

E=E∘+nF2.303RT​log[M][Mn+]​

E=E∘−nRT2.303F​log[M][Mn+]​

E=E∘−nF2.303RT​log[Mn+]

For Mn++ne−→M, E=E∘−nF2.303RT​log[Mn+]M​ =E∘+nF2.303RT​log[M][Mn+]​

$E = E^{\circ} + \frac{2.303 RT}{n F} lo g \frac{[ M ]}{[ M ^{n +} ]}$

$E = E^{\circ} + \frac{2.303 RT}{n F} lo g \frac{[ M ^{n +} ]}{[ M ]}$

$E = E^{\circ} - \frac{2.303 F}{n RT} lo g \frac{[ M ^{n +} ]}{[ M ]}$

$E = E^{\circ} - \frac{2.303 RT}{n F} lo g [M^{n +}]$

For $M n^{+} + n e^{-} \to M$ ,
$E = E^{\circ} - \frac{2.303 RT}{n F} lo g \frac{M}{[ M ^{n +} ]}$
$= E^{\circ} + \frac{2.303 RT}{n F} lo g \frac{[ M ^{n +} ]}{[ M ]}$