Question

The nature of curve of $E_{cell}^o$ against log $K_c$ is

• A. a straight line
• B. an elliptical curve
• C. a hyperbola
• D. parabola

Answer 1

Answer: (A)

$E=E^{\circ }-\frac{0.059}{n}lo{g}_{10}Q$

At equilibrium, $E=0,Q=K_c$

$E^{\circ }=\frac{0.059}{n}lo{g}_{10}{K}_c$

This equation is of the form y = mx, i.e., straight line, passing through origin.