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Chemistry
The nature of curve of Ec e l lo against log Kc is
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Q. The nature of curve of $E_{c e l l}^{o}$ against log $K_{c}$ is
NTA Abhyas
NTA Abhyas 2020
Electrochemistry
A
a straight line
45%
B
an elliptical curve
11%
C
a hyperbola
32%
D
parabola
11%
Solution:
$E=E^\circ -\frac{0.059}{n}log_{10}Q$
At equilibrium, $E=0,Q=K_{c}$
$E^\circ =\frac{0.059}{n}log_{10}K_{c}$
This equation is of the form y = mx, i.e., straight line, passing through origin.