The mutual electrostatic potential energy between two protons which are at a distance of 9× 10-15 m, in 92U235 nucleus is

Question

The mutual electrostatic potential energy between two protons which are at a distance of 9× 10-15 m, in 92U235 nucleus is (A)  1.56× 10-14J  (B)  5.5× 10-14J  (C)  2.56× 10-14J  (D)  4.56× 10-14J

Tardigrade Admin · Accepted Answer

Electrostatic potential energy U=(1/4 π ε0) (q1 q2/r) Here, q1=q2=1.6 × 10-19 C and r=9 × 10-15 m ∴ U = (9× 109 × 1.6 × 10-19 × 1.6 × 10-19/9× 10-15) = 2.56 × 10-14 J

Q. The mutual electrostatic potential energy between two protons which are at a distance of $9 \times 1 0^{- 15} m,$ in $_{92} U^{235}$ nucleus is

$1.56 \times 1 0^{- 14} J$

$5.5 \times 1 0^{- 14} J$

$2.56 \times 1 0^{- 14} J$

$4.56 \times 1 0^{- 14} J$

Q. The mutual electrostatic potential energy between two protons which are at a distance of 9×10−15m, in 92​U235 nucleus is

1.56×10−14J

5.5×10−14J

2.56×10−14J

4.56×10−14J

Electrostatic potential energy U=4πε0​1​rq1​q2​​ Here, q1​=q2​=1.6×10−19C and r=9×10−15m ∴U=9×10−159×109×1.6×10−19×1.6×10−19​ =2.56×10−14J

Q. The mutual electrostatic potential energy between two protons which are at a distance of $9 \times 1 0^{- 15} m,$ in $_{92} U^{235}$ nucleus is

$1.56 \times 1 0^{- 14} J$

$5.5 \times 1 0^{- 14} J$

$2.56 \times 1 0^{- 14} J$

$4.56 \times 1 0^{- 14} J$