Question

The motion of particle of mass $m$ is given by $y=ut+\frac{1}{2}g{t}^2$. The force acting on the particle is

• A. $mg$
• B. $\frac{mu}{t}$
• C. $2mg$
• D. $\frac{2mu}{t}$

Answer 1

Answer: (A)

Here, $y=ut+\frac{1}{2}g{t}^2$
$\therefore$ Velocity, $v=\frac{dy}{dt}$
$=u+gt$
Acceleration, $a=\frac{dv}{dt}=g$
The force acting on the particle is,
$F=ma=mg$