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Q.
The motion of particle of mass $m$ is given by $y=ut +\frac{1}{2} \,gt^{2}$. The force acting on the particle is
Laws of Motion
Solution:
Here, $y=u t+\frac{1}{2} g t^{2}$
$\therefore $ Velocity, $v=\frac{d\,y}{d \,t}$
$=u+gt$
Acceleration, $a=\frac{dv}{dt}=g$
The force acting on the particle is,
$F=ma=mg$