The motion of a simple pendulum excuting S.H.M. is represented by following equation. Y = A sin (π t +φ), where time is measured in second. The length of pendulum is :

Question

The motion of a simple pendulum excuting S.H.M. is represented by following equation. Y = A sin (π t +φ), where time is measured in second. The length of pendulum is : (A) 97.23 cm (B) 25.3 cm (C) 99.4 cm (D) 406.1 cm

Tardigrade Admin · Accepted Answer

ω=√( g /ℓ)=π ( g /ℓ)=π2 ⇒ ℓ=( g /π2) ℓ=(980/π2) ≈ 99.4 cm

Q. The motion of a simple pendulum excuting S.H.M. is represented by following equation. $Y = A sin (π t + ϕ)$ , where time is measured in second. The length of pendulum is :

97.23 cm

25.3 cm

99.4 cm

406.1 cm

$ω = \frac{g}{ℓ} = π$
$\frac{g}{ℓ} = π^{2} \Rightarrow ℓ = \frac{g}{π ^{2}}$
$ℓ = \frac{980}{π ^{2}} \approx 99.4 c m$

Q. The motion of a simple pendulum excuting S.H.M. is represented by following equation. Y=Asin(πt+ϕ), where time is measured in second. The length of pendulum is :