The motion of a particle is represented by the equation S = 8t3 - 2t2+ 6t + 7 . Find the velocity of the particle at the end of 2 seconds in m s-1

Question

The motion of a particle is represented by the equation S = 8t3 - 2t2+ 6t + 7 . Find the velocity of the particle at the end of 2 seconds in m s-1  (A)  108  (B)  57  (C)  94  (D)  41

Tardigrade Admin · Accepted Answer

S=8t3-2t2+6t+7 x=n (λ/t)=8 (3t2)-2(2t)+6(1)+7(0) =24t2-4t+6 At t=2 s, v=24(2)2-4(2)+6 =96-8+6 =94 m s-1

Q. The motion of a particle is represented by the equation $S = 8 t^{3} - 2 t^{2} + 6 t + 7$ . Find the velocity of the particle at the end of $2$ seconds in $m s^{- 1}$

$108$

$57$

$94$

$41$

$S = 8 t^{3} - 2 t^{2} + 6 t + 7$
$x = n \frac{λ}{t} = 8 (3 t^{2}) - 2 (2 t) + 6 (1) + 7 (0)$
$= 24 t^{2} - 4 t + 6$
At $t = 2 s$ ,
$v = 24 (2)^{2} - 4 (2) + 6$
$= 96 - 8 + 6$
$= 94 m s^{- 1}$

Q. The motion of a particle is represented by the equation S=8t3−2t2+6t+7 . Find the velocity of the particle at the end of 2 seconds in ms−1

108

57

94

41