Question

The most probable radius (in pm) for finding the electron in $H{e}^{+}$ is

• A. 0.0
• B. 52.9
• C. 26.5
• D. 105.8

Answer 1

Answer: (C)

Bohr's radius $(r)=\frac{59.2n^2}{Z}pm$
$n=$ number of the shell
$Z=$ atomic number
$r=\frac{52.9\times 1^2}{2}pm=26.45pm$