The moment of inertia of a uniform ring of mass M and radius r about a tangent lying in its own plane is

Question

The moment of inertia of a uniform ring of mass M and radius r about a tangent lying in its own plane is (A) 2 Mr 2 (B) 3 / 2 Mr 2 (C) Mr 2 (D) (M r2/2)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6c3dd86e21a6995606820fece85fea8e-.png" /> Moment of inertia of ring about his axis of rotation I=Mr2 According to the parallel axis theorem I=Mr2+Mr2 I=2 Mr2

Q. The moment of inertia of a uniform ring of mass $M$ and radius $r$ about a tangent lying in its own plane is

$2 M r^{2}$

$3/2 M r^{2}$

$M r^{2}$

$\frac{M r ^{2}}{2}$

Moment of inertia of ring about his axis of rotation
$I = M r^{2}$
According to the parallel axis theorem
$I = M r^{2} + M r^{2}$
$I = 2 M r^{2}$

Q. The moment of inertia of a uniform ring of mass M and radius r about a tangent lying in its own plane is

2Mr2

3/2Mr2

Mr2

2Mr2​