The moment of inertia of a thin square plate ABCD of uniform thickness about an axis passing through its centre and perpendicular to its plane will be:-

Question

The moment of inertia of a thin square plate ABCD of uniform thickness about an axis passing through its centre and perpendicular to its plane will be:- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vby63o3yzfrqytsi.jpg" /> (A) I1+I2 (B) I1-I3 (C) I1+I2+I4 (D) I1+I2+I3

Tardigrade Admin · Accepted Answer

⊥ axis theorem I2=I1+I2=I3+I4

Q. The moment of inertia of a thin square plate $A BC D$ of uniform thickness about an axis passing through its centre and perpendicular to its plane will be:-

$I_{1} + I_{2}$

$I_{1} - I_{3}$

$I_{1} + I_{2} + I_{4}$

$I_{1} + I_{2} + I_{3}$

$⊥$ axis theorem
$I_{2} = I_{1} + I_{2} = I_{3} + I_{4}$

Q. The moment of inertia of a thin square plate ABCD of uniform thickness about an axis passing through its centre and perpendicular to its plane will be:-

I1​+I2​

I1​−I3​

I1​+I2​+I4​

I1​+I2​+I3​