The moles of O2 required for reacting with 6.8g ammonia(...NH3 + .... O2----....NO +....H2O) is

Question

The moles of O2 required for reacting with 6.8g ammonia(...NH3 + .... O2---->....NO +....H2O) is (A) 5 (B) 2.5 (C) 1 (D) 0.5

Tardigrade Admin · Accepted Answer

The balanced equation is 4NH3+5O2→ 4NO+6H2O From the equation ; 4× 17 g of NH3 require O2=5 mol 6.8 g of NH3 require O2=(5×8.5/4×17) =0.5 mol

Q. The moles of $O_{2}$ required for reacting with 6.8g ammonia $(... N H_{3} + .... O_{2} - - - - > .... NO + .... H_{2} O)$ is