The molecule AB has a bond length of 1.61 mathringA a dipole moment of 0.38 D. The fractional charge on each atom is: (charge on .1 e -=-4.8 × 10-10 esu )

Question

The molecule AB has a bond length of 1.61 mathringA a dipole moment of 0.38 D. The fractional charge on each atom is: (charge on .1 e -=-4.8 × 10-10 esu ) (A) 0.5 (B) 0.05 (C) 0 (D) 1

Tardigrade Admin · Accepted Answer

1D =10-18 esu cm m = q × d 0.380= q × 1.61 mathringA 0.38 × 10-18 esu = q 1.61 × 10-8 cm q =(0.38 × 10-18/1.61 × 10-8)=0.23 × 10-10 esu Fractional charge on each atom =(0.23 × 10-10 esu /4.8 × 10-10 esu ) =0.05

Q. The molecule AB has a bond length of 1.61A˚ & a dipole moment of 0.38D. The fractional charge on each atom is: (charge on 1e−=−4.8×10−10esu)

0.5

0.05

0

1

1D=10−18 esu cm m=q×d 0.380=q×1.61A˚ 0.38×10−18esu=q1.61×10−8cm q=1.61×10−80.38×10−18​=0.23×10−10esu Fractional charge on each atom =4.8×10−10esu0.23×10−10esu​ =0.05

Q. The molecule $A B$ has a bond length of $1.61 \overset{˚}{A}$ & a dipole moment of $0.38 D$ . The fractional charge on each atom is: (charge on $1 e^{-} = - 4.8 \times 1 0^{- 10} es u)$