The molarity of the solution containing 2.8 % (mass/volume) solution of KOH is: (Given atomic mass of K = 39) is:

Question

The molarity of the solution containing 2.8 % (mass/volume) solution of KOH is: (Given atomic mass of K = 39) is: (A) 0.1 M (B) 0.5 M (C) 0.2 M (D) 1 M

Tardigrade Admin · Accepted Answer

Weight of KOH = 2.8 grams Volume of solution = 100 ml M = (2.8 × 1000/56× 100) = (28/56) = 0.5 M

Q. The molarity of the solution containing $2.8%$ (mass/volume) solution of $K O H$ is: (Given atomic mass of $K = 39$ ) is:

$0.1 M$

$0.5 M$

$0.2 M$

$1 M$

Weight of $K O H = 2.8$ grams
Volume of solution $= 100 m l$
$M = \frac{2.8 \times 1000}{56 \times 100} = \frac{28}{56} = 0.5 M$

Q. The molarity of the solution containing 2.8% (mass/volume) solution of KOH is: (Given atomic mass of K=39) is:

0.1M

0.5M

0.2M

1M