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  4. The molarity of the solution containing 2.8 % (mass/volume) solution of KOH is: (Given atomic mass of K = 39) is:

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Q. The molarity of the solution containing $2.8\%$ (mass/volume) solution of $KOH$ is: (Given atomic mass of $K = 39$) is:

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Solution:

Weight of $KOH = 2.8$ grams
Volume of solution $= 100 \,ml$
$M = \frac{2.8 \times 1000}{56\times 100} = \frac{28}{56} = 0.5\,M$