The molarity of pure water is:

Question

The molarity of pure water is: (A) 100 (B) 55.6 (C) 18 (D) 5.56

Tardigrade Admin · Accepted Answer

Molarity of pure water =55.6 At 25° C, density of water =1 gram / ml 1 g =1 ml So, 1000 g =1000 ml Number of moles of water =(1000/18)=55.55 mol Molarity of water =(55.6/1 L )=55.55 M

Q. The molarity of pure water is:

100

55.6

18

5.56

Molarity of pure water $= 55.6$
At $2 5^{\circ} C$ , density of water $= 1 g r am / m l$
$1 g = 1 m l$
So, $1000 g = 1000 m l$
Number of moles of water $= \frac{1000}{18} = 55.55 m o l$
Molarity of water $= \frac{55.6}{1 L} = 55.55 M$

Q. The molarity of pure water is:

100

55.6

18

5.56

Molarity of pure water =55.6 At 25∘C, density of water =1gram/ml 1g=1ml So, 1000g=1000ml Number of moles of water =181000​=55.55mol Molarity of water =1L55.6​=55.55M

Molarity of pure water $= 55.6$
At $2 5^{\circ} C$ , density of water $= 1 g r am / m l$
$1 g = 1 m l$
So, $1000 g = 1000 m l$
Number of moles of water $= \frac{1000}{18} = 55.55 m o l$
Molarity of water $= \frac{55.6}{1 L} = 55.55 M$