Question

The molarity of $HN{O}_3$ in a sample which has density 1.4 g / mL and mass percentage of 63% is __________. (Molecular Weight of $HN{O}_3=63$)

Answer 1

Answer: 14.00

$100gmsoln\to 63gmHN{O}_3$
$\frac{100}{1.4}mL\to 1moleHN{O}_3$
$Molarity=\frac{1}{\frac{100}{1.4}\times \frac{1}{1000}}=14M$