The molarity of a solution containing 5 g of NaOH in 450 mL solution will be

Question

The molarity of a solution containing 5 g of NaOH in 450 mL solution will be (A)  0.189 mol dm-3  (B)  0.278 mol dm-3  (C)  0.556 mol dm-3  (D)  0.027 mol dm-3

Tardigrade Admin · Accepted Answer

Molarity of the solution, if w gram of the solute is present in V mL of the solution M=(w/Molar mass of solute)× (1000/V) =(5/40)× (1000/450) =0.278 mol L-1 =0.278 mol dm-3

Q. The molarity of a solution containing $5 g$ of $N a O H$ in $450 m L$ solution will be

$0.189 m o l d m^{- 3}$

$0.278 m o l d m^{- 3}$

$0.556 m o l d m^{- 3}$

$0.027 m o l d m^{- 3}$

Molarity of the solution, if $w$ gram of the solute is present in V mL of the solution $M = \frac{w}{M o l a r ma ss o f so l u t e} \times \frac{1000}{V}$ $= \frac{5}{40} \times \frac{1000}{450}$ $= 0.278 m o l L^{- 1}$ $= 0.278 m o l d m^{- 3}$

Q. The molarity of a solution containing 5g of NaOH in 450mL solution will be

0.189moldm−3

0.278moldm−3

0.556moldm−3

0.027moldm−3