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Q. The molarity of a solution containing $ 5\,\,g $ of $ NaOH $ in $ 450\,\,mL $ solution will be

Rajasthan PMTRajasthan PMT 2011

Solution:

Molarity of the solution, if $ w $ gram of the solute is present in V mL of the solution $ M=\frac{w}{Molar\,\,mass\,\,of\,\,solute}\times \frac{1000}{V} $ $ =\frac{5}{40}\times \frac{1000}{450} $ $ =0.278\,\,mol\,\,{{L}^{-1}} $ $ =0.278\,\,mol\,\,d{{m}^{-3}} $