The molar solubility of Cd(OH)2 is 1.84 × 10-5 M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH = 12 is :

Question

The molar solubility of Cd(OH)2 is 1.84 × 10-5 M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH = 12 is : (A)  6.23 × 10-11 M (B)  1.84 × 10-9 M (C) (2.49/1.84) × 10-9 M (D)  2.49 × 10-10 M

Tardigrade Admin · Accepted Answer

Ksp = 4 (s)3 = 4 × ( 1.84 × 10-5)3 Cd(OH)2 leftharpoons Cd2+ + 2OH- S' S' (10-2 + S') ≃ 10-2 S' × (102)2 = 4 × (1.84 × 10-5 )3 S' = 4 × (1.84)3 × 1011 (S') = 2.491 × 10-10 M

Q. The molar solubility of $C d (O H)_{2}$ is $1.84 \times 1 0^{- 5} M$ in water. The expected solubility of $C d (O H)_{2}$ in a buffer solution of $p H = 12$ is :

$6.23 \times 1 0^{- 11} M$

$1.84 \times 1 0^{- 9} M$

$\frac{2.49}{1.84} \times 1 0^{- 9} M$

$2.49 \times 1 0^{- 10} M$

Q. The molar solubility of Cd(OH)2​ is 1.84×10−5M in water. The expected solubility of Cd(OH)2​ in a buffer solution of pH=12 is :

6.23×10−11M

1.84×10−9M

1.842.49​×10−9M

2.49×10−10M

Ksp​=4(s)3 =4×(1.84×10−5)3 Cd(OH)2​⇌Cd2++2OH− S′S′(10−2+S′)≃10−2 S′×(102)2=4×(1.84×10−5)3 S′=4×(1.84)3×1011 (S′)=2.491×10−10M

Q. The molar solubility of $C d (O H)_{2}$ is $1.84 \times 1 0^{- 5} M$ in water. The expected solubility of $C d (O H)_{2}$ in a buffer solution of $p H = 12$ is :

$6.23 \times 1 0^{- 11} M$

$1.84 \times 1 0^{- 9} M$

$\frac{2.49}{1.84} \times 1 0^{- 9} M$

$2.49 \times 1 0^{- 10} M$