The molar ratio of Fe++ to Fe+++ in a mixture of FeSO4 and Fe2(SO4)3 having equal number of sulphate ions in both ferrous and ferric sulphate is:

Question

The molar ratio of Fe++ to Fe+++ in a mixture of FeSO4 and Fe2(SO4)3 having equal number of sulphate ions in both ferrous and ferric sulphate is: (A) 1: 2 (B) 3 :2 (C) 2: 3 (D) can’t be determined

Tardigrade Admin · Accepted Answer

FeSO4 1 mole of SO2-4 =1 mole Fe2+ In Fe2(SO4)3 3 moles of SO2-4= 2 moles Fe3+ 1 mole of S042-=(2/3) moles Fe3+ ratio =(Fe2+/Fe3+)=(1/2)=(3/2)

Q. The molar ratio of $F e^{++}$ to $F e^{+++}$ in a mixture of $F e S O_{4}$ and $F e_{2} (S O_{4})_{3}$ having equal number of sulphate ions in both ferrous and ferric sulphate is:

$1 : 2$

$3 : 2$

$2 : 3$

can’t be determined

$F e S O_{4}$
1 mole of $S O_{4}^{2 -} = 1$ mole $F e^{2 +}$
$I n F e_{2} (S O_{4})_{3}$
3 moles of $S O_{4}^{2 -} = 2$ moles $F e^{3 +}$
1 mole of $S 0_{4}^{2 -} = \frac{2}{3}$ moles $F e^{3 +}$
ratio $= \frac{F e ^{2 +}}{F e ^{3 +}} = \frac{1}{2} = \frac{3}{2}$

Q. The molar ratio of Fe++ to Fe+++ in a mixture of FeSO4​ and Fe2​(SO4​)3​ having equal number of sulphate ions in both ferrous and ferric sulphate is:

1:2

3:2

2:3