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  4. The molar ratio of Fe++ to Fe+++ in a mixture of FeSO4 and Fe2(SO4)3 having equal number of sulphate ions in both ferrous and ferric sulphate is:

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Q. The molar ratio of $Fe^{++}$ to $Fe^{+++}$ in a mixture of $FeSO_4$ and $Fe_{2}(SO_{4})_{3}$ having equal number of sulphate ions in both ferrous and ferric sulphate is:

Redox Reactions

Solution:

$FeSO_{4}$
1 mole of $SO^{2-}_{4} =1$ mole $Fe^{2+}$
$In Fe_{2}\left(SO_{4}\right)_{3}$
3 moles of $SO^{2-}_{4}= 2 $moles $Fe^{3+}$
1 mole of $S0_{4}^{2-}=\frac{2}{3}$ moles $Fe^{3+} $
ratio $=\frac{Fe^{2+}}{Fe^{3+}}=\frac{1}{2}=\frac{3}{2}$