The molar heat capacity (Cp) of CD2O is 10 cals at 1000 K. The change in entropy associated with cooling of 32 g of CD2O vapour from 1000 K to 100 K at constant pressure will be: (D = deuterium, at. mass = 2 u)

Question

The molar heat capacity (Cp) of CD2O is 10 cals at 1000 K. The change in entropy associated with cooling of 32 g of CD2O vapour from 1000 K to 100 K at constant pressure will be: (D = deuterium, at. mass = 2 u) (A) 23.03 cal deg-1 (B) -23.03 cal deg-1 (C) 2.303 cal deg-1 (D) -2.303 cal deg-1

Tardigrade Admin · Accepted Answer

Δ S= nCp ℓ n ((T2/T1)) =2.303× n× cp log ((T2/T1)) =2.303×1×10 log (100/1000) =-23.03 cal deg-1

Q. The molar heat capacity $(C_{p})$ of $C D_{2} O$ is 10 cals at 1000 K. The change in entropy associated with cooling of 32 g of $C D_{2} O$ vapour from 1000 K to 100 K at constant pressure will be : (D = deuterium, at. mass = 2 u)

$23.03 c a l d e g^{- 1}$

$- 23.03 c a l d e g^{- 1}$

$2.303 c a l d e g^{- 1}$

$- 2.303 c a l d e g^{- 1}$

$Δ S =_{n} C_{p} ℓ n (\frac{T _{2}}{T _{1}})$

$= 2.303 \times n \times c_{p} l o g (\frac{T _{2}}{T _{1}})$

$= 2.303 \times 1 \times 10 l o g \frac{100}{1000}$

$= - 23.03 c a l d e g^{- 1}$

Q. The molar heat capacity (Cp​) of CD2​O is 10 cals at 1000 K. The change in entropy associated with cooling of 32 g of CD2​O vapour from 1000 K to 100 K at constant pressure will be : (D = deuterium, at. mass = 2 u)

23.03caldeg−1

−23.03caldeg−1

2.303caldeg−1

−2.303caldeg−1