The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76 × 10-3 S cm-1 at 298 K is

Question

The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76 × 10-3 S cm-1 at 298 K is (A) 2.88 S cm2 / mol (B) 11.52 S cm2 / mol (C) 0.086 S cm2 / mol (D) 28.8 S cm2 / mol

Tardigrade Admin · Accepted Answer

Lambda m=(k× 100/m)=(5.76× 1-3× 1000/0.5) =11.52 Scm2/mol

Q. The molar conductivity of a $0.5 m o l / d m^{3}$ solution of $A g N O^{3}$ with electrolytic conductivity of $5.76 \times 1 0^{- 3} S c m^{- 1}$ at $298 K$ is

$2.88 S c m^{2} / m o l$

$11.52 S c m^{2} / m o l$

$0.086 S c m^{2} / m o l$

$28.8 S c m^{2} / m o l$

$Λ_{m} = \frac{k \times 100}{m} = \frac{5.76 \times 1 ^{- 3} \times 1000}{0.5}$
$= 11.52 S c m^{2} / m o l$

Q. The molar conductivity of a 0.5mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76×10−3Scm−1 at 298K is

2.88Scm2/mol

11.52Scm2/mol

0.086Scm2/mol

28.8Scm2/mol