The molar conductivities of HCl, NaCl, CH3COOH and CH3COONa at infinite dilution follow the order

Question

The molar conductivities of HCl, NaCl, CH3COOH and CH3COONa at infinite dilution follow the order (A) HCl > CH3 COOH > NaCl > CH3 COONa (B) CH3 COONa > HCl > NaCl > CH3 COOH (C) HCl > NaCl > CH3 COOH > CH3 COONa (D) CH3 COOH > CH3 COONa > HCl > NaCl

Tardigrade Admin · Accepted Answer

Molar conductivity always increases with increase in concentration of electrolyte. Among the given compounds, the molar conductivity depends upon the concentration of

H^{+}

ions. Thus, stronger the acid more will be

H^{+}

ions and more will be the molar conductivity. The order of acidic strength is

Strong acid H Cl > Weak acid C H_{3} COO > Neutral salt N a Cl > Salt of weak acid C H_{3} COON a

Thus, molar conductivity at infinite dilution follows the order

H Cl > C H_{3} COO H > N a Cl > C H_{3} COON a

Q. The molar conductivities of $H Cl, N a Cl, C H_{3} COO H$ and $C H_{3} COON a$ at infinite dilution follow the order

$H Cl > C H_{3} COO H > N a Cl > C H_{3} COON a$

$C H_{3} COON a > H Cl > N a Cl > C H_{3} COO H$

$H Cl > N a Cl > C H_{3} COO H > C H_{3} COON a$

$C H_{3} COO H > C H_{3} COON a > H Cl > N a Cl$

Q. The molar conductivities of HCl,NaCl,CH3​COOH and CH3​COONa at infinite dilution follow the order

HCl>CH3​COOH>NaCl>CH3​COONa

CH3​COONa>HCl>NaCl>CH3​COOH

HCl>NaCl>CH3​COOH>CH3​COONa

CH3​COOH>CH3​COONa>HCl>NaCl

Q. The molar conductivities of $H Cl, N a Cl, C H_{3} COO H$ and $C H_{3} COON a$ at infinite dilution follow the order

$H Cl > C H_{3} COO H > N a Cl > C H_{3} COON a$

$C H_{3} COON a > H Cl > N a Cl > C H_{3} COO H$

$H Cl > N a Cl > C H_{3} COO H > C H_{3} COON a$

$C H_{3} COO H > C H_{3} COON a > H Cl > N a Cl$