The molality of a 10 % (v/v) solution of di-bromine solution in CCl 4 (carbon tetrachloride) is ' x '. x= × 10-2 M. (Nearest integer) [Given: molar mass of Br 2=160 g mol -1 atomic mass of C =12 g mol -1 atomic mass of Cl =35.5 g mol -1 density of dibromine =3.2 g cm -3 density of CCl 4=1.6 g cm -3 ]

Question

The molality of a 10 % (v/v) solution of di-bromine solution in CCl 4 (carbon tetrachloride) is ' x '. x= × 10-2 M. (Nearest integer) [Given: molar mass of Br 2=160 g mol -1 atomic mass of C =12 g mol -1 atomic mass of Cl =35.5 g mol -1 density of dibromine =3.2 g cm -3 density of CCl 4=1.6 g cm -3 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

( 10 ml solute in 90 ml solvent mass of solute =10 × 3.2=32 g mass of solvent =90 × 1.6 g m =(32 × 1000/160 × 90 × 1.6)=1.388 m-138.8 × 10-2-139

( 10ml solute in 90ml solvent mass of solute =10×3.2=32g mass of solvent =90×1.6g m=160×90×1.632×1000​=1.388 m−138.8×10−2−139

( $10 m l$ solute in $90 m l$ solvent
mass of solute $= 10 \times 3.2 = 32 g$
mass of solvent $= 90 \times 1.6 g$
$m = \frac{32 \times 1000}{160 \times 90 \times 1.6} = 1.388$
$m - 138.8 \times 1 0^{- 2} - 139$