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Tardigrade
Question
Mathematics
The modulus of the complex number z=((1-i√3)(cos θ+i sin θ)/2(1-i)(cos θ-i sin θ)) is
Q. The modulus of the complex number
z
=
2
(
1
−
i
)
(
cos
θ
−
i
s
in
θ
)
(
1
−
i
3
)
(
cos
θ
+
i
s
in
θ
)
is
4757
222
Complex Numbers and Quadratic Equations
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A
2
2
1
19%
B
3
1
21%
C
2
1
39%
D
2
3
21%
Solution:
∣
cos
θ
+
i
s
in
θ
∣
=
∣
cos
θ
−
i
s
in
θ
∣
=
1
∴
∣
z
∣
=
2
∣
1
−
i
∣
∣
1
−
i
3
∣
=
2
2
2
=
2
1