Q. The modulus of $\frac{( 1 + i 3 ) ( 2 + 2 i )}{( 3 - i )}$ is

7302 191 Complex Numbers and Quadratic Equations Report Error

A

$2$

13%

B

$4$

17%

C

$32$

39%

D

$22$

31%

Solution:

$∣ ∣ \frac{( 1 + i 3 ) ( 2 + 2 i )}{3 - i} ∣ ∣ = \frac{∣ 1 + i 3 ∣ ∣ 2 + 2 i ∣}{∣ 3 - i ∣}$
$= \frac{2 \times 2 2}{2} = 22$