The minimum velocity (in ms -1 ) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is :

Question

The minimum velocity (in ms -1 ) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is : (A) 60 (B) 30 (C) 15 (D) 25

Tardigrade Admin · Accepted Answer

Using the relation (m v2/r)=μ R, R=m g (m v2/r)=μ m g or v2=μ r g or v2=0.6 × 150 × 10 ⇒ v=30 m / s

Q. The minimum velocity (in $m s^{- 1}$ ) with which a car driver must traverse a flat curve of radius $150 m$ and coefficient of friction $0.6$ to avoid skidding is :

60

30

15

25

Using the relation
$\frac{m v ^{2}}{r} = μ R, R = m g$
$\frac{m v ^{2}}{r} = μ m g$ or $v^{2} = μ r g$
or $v^{2} = 0.6 \times 150 \times 10$
$\Rightarrow v = 30 m / s$

Q. The minimum velocity (in ms−1 ) with which a car driver must traverse a flat curve of radius 150m and coefficient of friction 0.6 to avoid skidding is :

60

30

15

25

Using the relation rmv2​=μR,R=mg rmv2​=μmg or v2=μrg or v2=0.6×150×10 ⇒v=30m/s

Q. The minimum velocity (in $m s^{- 1}$ ) with which a car driver must traverse a flat curve of radius $150 m$ and coefficient of friction $0.6$ to avoid skidding is :

Using the relation
$\frac{m v ^{2}}{r} = μ R, R = m g$
$\frac{m v ^{2}}{r} = μ m g$ or $v^{2} = μ r g$
or $v^{2} = 0.6 \times 150 \times 10$
$\Rightarrow v = 30 m / s$