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Tardigrade
Question
Mathematics
The minimum value of the function f ( x )=2 x 3-3 x 2-12 x +6 on the set A = x mid ln x > ln ( x 2-3 x +3)
Q. The minimum value of the function
f
(
x
)
=
2
x
3
−
3
x
2
−
12
x
+
6
on the set
A
=
{
x
∣
ln
x
>
ln
(
x
2
−
3
x
+
3
)
}
135
158
Application of Derivatives
Report Error
A
- 14
B
0
C
- 4
D
4
Solution:
Correct answer is (a) - 14
