Question

The minimum value of $e^{(2x^2-2x+1){\sin }^{2}x}$ is

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (B)

Given, $y=e^{(2x^2-2x+1){\sin }^{2}x}$
$2x^2-2x+1>0$
for all $x,$
$y$ is minimum for $sinx=0$
$\Rightarrow$ $x=0$
$\therefore$ $y_{\min }=e^0=1$