Question

The minimum pressure required to compress $600d{m}^3$ of a gas at $1$ bar to $150d{m}^3$ at $40^{\circ }C$ is

• A. $4.0$ bar
• B. $0.2$ bar
• C. $1.0$ bar
• D. $2.5$ bar

Answer 1

Answer: (A)

By Boyle's law
$P_1{V}_1=P_2{V}_2$
$1$ bar $\times 600d{m}^3=P_2\times 150d{m}^3$
$P_2=4$ bar